(x^2+3)-7(x^2+3)+12=0

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Solution for (x^2+3)-7(x^2+3)+12=0 equation:


Simplifying
(x2 + 3) + -7(x2 + 3) + 12 = 0

Reorder the terms:
(3 + x2) + -7(x2 + 3) + 12 = 0

Remove parenthesis around (3 + x2)
3 + x2 + -7(x2 + 3) + 12 = 0

Reorder the terms:
3 + x2 + -7(3 + x2) + 12 = 0
3 + x2 + (3 * -7 + x2 * -7) + 12 = 0
3 + x2 + (-21 + -7x2) + 12 = 0

Reorder the terms:
3 + -21 + 12 + x2 + -7x2 = 0

Combine like terms: 3 + -21 = -18
-18 + 12 + x2 + -7x2 = 0

Combine like terms: -18 + 12 = -6
-6 + x2 + -7x2 = 0

Combine like terms: x2 + -7x2 = -6x2
-6 + -6x2 = 0

Solving
-6 + -6x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + -6x2 = 0 + 6

Combine like terms: -6 + 6 = 0
0 + -6x2 = 0 + 6
-6x2 = 0 + 6

Combine like terms: 0 + 6 = 6
-6x2 = 6

Divide each side by '-6'.
x2 = -1

Simplifying
x2 = -1

Reorder the terms:
1 + x2 = -1 + 1

Combine like terms: -1 + 1 = 0
1 + x2 = 0

The solution to this equation could not be determined.

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